python中实现witch case

方案一

参考链接
https://www.cnblogs.com/dbf-/p/10601216.html
如果只是简单使用，那这里方案一的方法更简明一些。

def case1():                            # 第一种情况执行的函数
    print('This is the case1')


def case2():                            # 第二种情况执行的函数
    print('This is the case2')


def case3():                            # 第三种情况执行的函数
    print('This is the case3')
def default():                          # 默认情况下执行的函数
    print('No such case')

switch = {'case1': case1,                # 注意此处不要加括号
          'case2': case2,
          'case3': case3,
          }

choice = 'case1'                         # 获取选择
switch.get(choice, default)()            # 执行对应的函数，如果没有就执行默认的函数
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方案二

参考链接
https://blog.csdn.net/l460133921/article/details/74892476
这篇文章中还有把 switch 写成类

def success(msg):
    print msg

def debug(msg):
    print msg

def error(msg):
    print msg

def warning(msg):
    print msg

def other(msg):
    print msg

def notify_result(num, msg):
    numbers = {
        0 : success,
        1 : debug,
        2 : warning,
        3 : error
    }

    method = numbers.get(num, other)
    if method:
        method(msg)

if __name__ == "__main__":
    notify_result(0, "success")
    notify_result(1, "debug")
    notify_result(2, "warning")
    notify_result(3, "error")
    notify_result(4, "other")
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